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A train of certain length is moving at a speed of 25 kmph. It will cross a man coming from the opposite direction at a speed of 2 km per hour in 44 seconds. What is the length of the train?

💡First, I need to determine the relative speed between the train and the man since they are moving in opposite directions. The train is moving at 25 km/h, and the man is moving at 2 km/h. Adding these speeds gives a relative speed of 27 km/h.Next, I should convert this relative speed from kilometers per hour to meters per second to match the time unit provided in seconds. Using the conversion factor, 27 km/h is equivalent to 7.5 m/s.Finally, with the relative speed in meters per second and the time it takes for the train to pass the man, I can calculate the length of the train by multiplying the relative speed by the time. This gives me the length of the train as 330 meters.

Elective 4-4: Coordinate System and Parametric EquationsIn the Cartesian coordinate system xoy, the parametric equation of circle C is begin{cases} & x=-5+sqrt{2}cos t & y=3+sqrt{2}sin t end{cases}, (t is the parameter), in the polar coordinate system with the origin O as the pole and the non-negative half-axis of x as the polar axis, the polar equation of line l is rho cos (theta +frac{pi }{4})=-sqrt{2}, the polar coordinates of points A,B are respectively A(2,frac{pi }{2}),B(2,pi)(1) Find the standard equation of circle C and the Cartesian equation of line l;(2) Point P is any point on circle C, find the minimum value of the area of Delta PAB.

💡Alright, so I have this problem about coordinate systems and parametric equations. It's divided into two parts. Let me try to tackle each part step by step.Starting with part (1): I need to find the standard equation of circle C and the Cartesian equation of line l.First, the parametric equations for circle C are given as:[begin{cases}x = -5 + sqrt{2}cos t y = 3 + sqrt{2}sin tend{cases}]where ( t ) is the parameter. I remember that parametric equations for a circle usually have the form ( x = h + rcos t ) and ( y = k + rsin t ), where ( (h, k) ) is the center and ( r ) is the radius. So, comparing, it looks like the center of the circle is at ( (-5, 3) ) and the radius is ( sqrt{2} ). To write the standard equation, I just need to square both ( x + 5 ) and ( y - 3 ) and set their sum equal to ( (sqrt{2})^2 = 2 ). So, the standard equation should be:[(x + 5)^2 + (y - 3)^2 = 2]That seems straightforward.Next, the polar equation of line ( l ) is given as:[rho cosleft(theta + frac{pi}{4}right) = -sqrt{2}]I need to convert this into Cartesian coordinates. I recall that in polar coordinates, ( rho cos(theta + phi) ) can be expanded using the cosine addition formula:[cos(theta + phi) = costheta cosphi - sintheta sinphi]So, substituting ( phi = frac{pi}{4} ), we have:[rho left( costheta cosfrac{pi}{4} - sintheta sinfrac{pi}{4} right) = -sqrt{2}]Since ( cosfrac{pi}{4} = sinfrac{pi}{4} = frac{sqrt{2}}{2} ), this simplifies to:[rho left( frac{sqrt{2}}{2} costheta - frac{sqrt{2}}{2} sintheta right) = -sqrt{2}]Multiplying through by ( frac{2}{sqrt{2}} ) to simplify, we get:[rho costheta - rho sintheta = -2]But in Cartesian coordinates, ( rho costheta = x ) and ( rho sintheta = y ). So substituting these in, the equation becomes:[x - y = -2]Or rearranged:[x - y + 2 = 0]So, the Cartesian equation of line ( l ) is ( x - y + 2 = 0 ).Moving on to part (2): I need to find the minimum value of the area of triangle ( PAB ) where ( P ) is any point on circle ( C ).First, the points ( A ) and ( B ) are given in polar coordinates: ( A(2, frac{pi}{2}) ) and ( B(2, pi) ). I should convert these to Cartesian coordinates to work with them more easily.For point ( A ):[x = 2 cosleft( frac{pi}{2} right) = 0 y = 2 sinleft( frac{pi}{2} right) = 2]So, ( A ) is at ( (0, 2) ).For point ( B ):[x = 2 cos(pi) = -2 y = 2 sin(pi) = 0]So, ( B ) is at ( (-2, 0) ).Now, I need to find the area of triangle ( PAB ) where ( P ) is any point on circle ( C ). The area of a triangle given three points can be found using the formula:[text{Area} = frac{1}{2} | vec{AB} times vec{AP} |]But maybe it's easier to use the formula involving base and height. Alternatively, since I know the coordinates of all three points, I can use the shoelace formula.But perhaps a more efficient method is to realize that the area of triangle ( PAB ) can be expressed as ( frac{1}{2} times text{base} times text{height} ). Here, I can take ( AB ) as the base and the distance from point ( P ) to line ( AB ) as the height.First, let's compute the length of ( AB ). Points ( A(0, 2) ) and ( B(-2, 0) ).The distance between ( A ) and ( B ) is:[|AB| = sqrt{(0 - (-2))^2 + (2 - 0)^2} = sqrt{(2)^2 + (2)^2} = sqrt{4 + 4} = sqrt{8} = 2sqrt{2}]So, the base length is ( 2sqrt{2} ).Now, I need to find the distance from point ( P ) to the line ( AB ). Wait, but line ( AB ) is the same as line ( l ) from part (1), right? Because line ( l ) has equation ( x - y + 2 = 0 ). Let me check if points ( A ) and ( B ) lie on this line.For point ( A(0, 2) ):[0 - 2 + 2 = 0 quad text{True}]For point ( B(-2, 0) ):[-2 - 0 + 2 = 0 quad text{True}]Yes, both points lie on line ( l ), so line ( AB ) is indeed line ( l ). Therefore, the distance from ( P ) to line ( AB ) is the same as the distance from ( P ) to line ( l ).So, the area of triangle ( PAB ) is:[text{Area} = frac{1}{2} times |AB| times d = frac{1}{2} times 2sqrt{2} times d = sqrt{2} times d]Where ( d ) is the distance from ( P ) to line ( l ).Therefore, to minimize the area, I need to minimize ( d ), the distance from ( P ) to line ( l ).Given that ( P ) is any point on circle ( C ), which has equation ( (x + 5)^2 + (y - 3)^2 = 2 ). So, I need to find the minimum distance from any point on this circle to the line ( x - y + 2 = 0 ).I remember that the distance from a point ( (x_0, y_0) ) to the line ( ax + by + c = 0 ) is given by:[d = frac{|ax_0 + by_0 + c|}{sqrt{a^2 + b^2}}]In our case, the line is ( x - y + 2 = 0 ), so ( a = 1 ), ( b = -1 ), ( c = 2 ).So, the distance from ( P(x, y) ) to line ( l ) is:[d = frac{|x - y + 2|}{sqrt{1 + 1}} = frac{|x - y + 2|}{sqrt{2}}]But ( P ) lies on circle ( C ), so ( x = -5 + sqrt{2}cos t ) and ( y = 3 + sqrt{2}sin t ). Let me substitute these into the distance formula.Substituting ( x ) and ( y ):[d = frac{|(-5 + sqrt{2}cos t) - (3 + sqrt{2}sin t) + 2|}{sqrt{2}} = frac{|-5 + sqrt{2}cos t - 3 - sqrt{2}sin t + 2|}{sqrt{2}}]Simplify the numerator:[-5 - 3 + 2 = -6 sqrt{2}cos t - sqrt{2}sin t = sqrt{2}(cos t - sin t)]So, the numerator becomes:[|-6 + sqrt{2}(cos t - sin t)|]Therefore, the distance ( d ) is:[d = frac{|-6 + sqrt{2}(cos t - sin t)|}{sqrt{2}} = frac{|-6 + sqrt{2}(cos t - sin t)|}{sqrt{2}}]I can factor out ( sqrt{2} ) from the numerator:[d = frac{|-6 + sqrt{2}(cos t - sin t)|}{sqrt{2}} = frac{|-6 + sqrt{2} cdot sqrt{2} left( frac{cos t - sin t}{sqrt{2}} right)|}{sqrt{2}} ]Wait, that might complicate things. Alternatively, I can write ( cos t - sin t ) as ( sqrt{2} cos(t + frac{pi}{4}) ) using the identity ( cos t - sin t = sqrt{2} cos(t + frac{pi}{4}) ). Let me verify that:Using the identity:[cos t - sin t = sqrt{2} cosleft(t + frac{pi}{4}right)]Yes, that's correct because:[sqrt{2} cosleft(t + frac{pi}{4}right) = sqrt{2} left( cos t cosfrac{pi}{4} - sin t sinfrac{pi}{4} right) = sqrt{2} left( frac{sqrt{2}}{2} cos t - frac{sqrt{2}}{2} sin t right) = cos t - sin t]Perfect. So, substituting back into ( d ):[d = frac{|-6 + sqrt{2} cdot sqrt{2} cosleft(t + frac{pi}{4}right)|}{sqrt{2}} = frac{|-6 + 2 cosleft(t + frac{pi}{4}right)|}{sqrt{2}}]Simplify:[d = frac{|-6 + 2 cosleft(t + frac{pi}{4}right)|}{sqrt{2}} = frac{|2 cosleft(t + frac{pi}{4}right) - 6|}{sqrt{2}} = frac{|2(cosleft(t + frac{pi}{4}right) - 3)|}{sqrt{2}}]Wait, that doesn't seem helpful. Alternatively, perhaps I can factor out the 2:[d = frac{2 |cosleft(t + frac{pi}{4}right) - 3|}{sqrt{2}} = sqrt{2} |cosleft(t + frac{pi}{4}right) - 3|]But ( cos ) function ranges between -1 and 1, so ( cosleft(t + frac{pi}{4}right) - 3 ) ranges between -4 and -2. Therefore, the absolute value becomes:[|cosleft(t + frac{pi}{4}right) - 3| = 3 - cosleft(t + frac{pi}{4}right)]So, substituting back:[d = sqrt{2} left( 3 - cosleft(t + frac{pi}{4}right) right)]Therefore, the distance ( d ) is:[d = sqrt{2} left( 3 - cosleft(t + frac{pi}{4}right) right)]To find the minimum distance, we need to minimize ( d ). Since ( cosleft(t + frac{pi}{4}right) ) has a maximum value of 1 and a minimum value of -1, the expression ( 3 - cosleft(t + frac{pi}{4}right) ) will be minimized when ( cosleft(t + frac{pi}{4}right) ) is maximized, i.e., when ( cosleft(t + frac{pi}{4}right) = 1 ).So, the minimum value of ( d ) is:[d_{text{min}} = sqrt{2} (3 - 1) = sqrt{2} times 2 = 2sqrt{2}]Therefore, the minimum distance from ( P ) to line ( l ) is ( 2sqrt{2} ).Now, going back to the area of triangle ( PAB ):[text{Area} = sqrt{2} times d]Substituting ( d_{text{min}} = 2sqrt{2} ):[text{Area}_{text{min}} = sqrt{2} times 2sqrt{2} = 2 times 2 = 4]So, the minimum area of triangle ( PAB ) is 4.Wait, let me double-check my steps to make sure I didn't make a mistake.1. Converted parametric equations to standard circle equation: correct.2. Converted polar equation of line to Cartesian: correct, got ( x - y + 2 = 0 ).3. Converted points ( A ) and ( B ) to Cartesian: correct, ( A(0,2) ) and ( B(-2,0) ).4. Calculated distance ( AB ): correct, ( 2sqrt{2} ).5. Expressed area in terms of distance from ( P ) to line ( AB ): correct.6. Expressed distance from ( P ) to line ( l ) using parametric equations: correct.7. Used trigonometric identity to simplify: correct, ( cos t - sin t = sqrt{2} cos(t + pi/4) ).8. Expressed distance ( d ) in terms of ( cos(t + pi/4) ): correct.9. Found the minimum distance by considering the range of cosine: correct, minimum when cosine is 1, giving ( 2sqrt{2} ).10. Calculated minimum area: correct, ( sqrt{2} times 2sqrt{2} = 4 ).Everything seems to check out. So, I think the minimum area is indeed 4.**Final Answer**The minimum value of the area of triangle ( Delta PAB ) is boxed{4}.

What quantity of water should be taken out to concentrate 24 liters of a certain percentage acidic liquid to 60% acidic liquid if 8 liters of water need to be removed?

💡Okay, so I have this problem here: "What quantity of water should be taken out to concentrate 24 liters of a certain percentage acidic liquid to 60% acidic liquid if 8 liters of water need to be removed?" Hmm, that's a bit confusing at first glance. Let me try to break it down.First, I need to understand what's being asked. It seems like we have 24 liters of an acidic liquid, and we want to make it more concentrated—specifically, to 60% acidity. To do this, we need to remove some water. The problem mentions that 8 liters of water need to be removed, but it's asking for the quantity of water to be taken out. Wait, that seems a bit contradictory. If it's already stating that 8 liters need to be removed, why is it asking for the quantity? Maybe I'm misinterpreting it.Let me read it again: "What quantity of water should be taken out to concentrate 24 liters of a certain percentage acidic liquid to 60% acidic liquid if 8 liters of water need to be removed?" Okay, perhaps it's saying that in order to achieve the concentration of 60%, 8 liters of water need to be removed, and it's asking for the quantity of water that should be taken out. That still seems a bit circular. Maybe it's a translation issue or a typo.Assuming that the problem is asking: "What quantity of water should be taken out to concentrate 24 liters of a certain percentage acidic liquid to 60% acidic liquid?" and it's given that 8 liters of water need to be removed. Wait, that still doesn't make sense. If it's given that 8 liters need to be removed, then why is it asking for the quantity? Perhaps the original problem was different, and there was a mistake in the translation or wording.Alternatively, maybe the problem is stating that 8 liters of water need to be removed to achieve a certain concentration, and now it's asking for the quantity of water to be removed to reach 60% acidity. That would make more sense. So, perhaps the initial concentration is different, and removing 8 liters brings it to a certain concentration, and now we need to find out how much more water needs to be removed to get it to 60%.But the problem as stated is a bit unclear. Let me try to rephrase it: We have 24 liters of an acidic liquid with an unknown concentration. We need to remove some water to make it 60% acidic. It's given that 8 liters of water need to be removed. So, perhaps the question is confirming that 8 liters is the correct amount to remove to reach 60% acidity, and it's asking for the quantity, which is 8 liters. But that seems too straightforward.Alternatively, maybe the problem is saying that 8 liters of water need to be removed to achieve a certain concentration, and now we need to find out how much water needs to be removed to reach 60% acidity. In that case, we would need to know the initial concentration or the concentration after removing 8 liters.Wait, the problem doesn't mention the initial concentration or the concentration after removing 8 liters. It only mentions that 8 liters need to be removed to reach 60% acidity. So, perhaps the answer is simply 8 liters. But that seems too simple, and the problem is phrased in a way that suggests it's asking for a calculation.Maybe I'm overcomplicating it. Let's try to approach it step by step. We have 24 liters of an acidic liquid. Let's assume that the acidic liquid is a mixture of acid and water. The total volume is 24 liters. We need to remove some water to increase the concentration of acid to 60%. The problem states that 8 liters of water need to be removed. So, perhaps it's asking us to confirm that removing 8 liters of water will result in a 60% concentration.But to confirm that, we need to know the initial concentration of the acid. Without knowing the initial concentration, we can't verify if removing 8 liters of water will indeed result in a 60% concentration. Therefore, the problem might be incomplete or missing some information.Alternatively, maybe the problem is asking us to find out how much water needs to be removed to reach 60% acidity, and it's given that 8 liters need to be removed. But that still doesn't make sense because it's both asking and providing the answer.Perhaps there's a misunderstanding in the translation or wording. Maybe it's supposed to say that 8 liters of acid need to be added, or 8 liters of the solution need to be removed. That would make the problem more solvable.Assuming that the problem is asking: "What quantity of water should be taken out to concentrate 24 liters of a certain percentage acidic liquid to 60% acidic liquid?" and it's given that 8 liters of water need to be removed, then the answer would simply be 8 liters. But that seems too straightforward, and the problem is likely expecting a calculation.Alternatively, if the problem is saying that 8 liters of water need to be removed to achieve a certain concentration, and now we need to find out how much more water needs to be removed to reach 60%, then we would need to know the initial concentration or the concentration after removing 8 liters.Given the ambiguity, perhaps the best approach is to assume that the problem is asking for the quantity of water to be removed to reach 60% acidity, and it's given that 8 liters need to be removed. Therefore, the answer is 8 liters.But to be thorough, let's consider the possibility that the problem is missing some information. If we assume that the initial concentration is, say, 50%, then we can calculate how much water needs to be removed to reach 60%. Let's try that.Let's denote:- V = total volume = 24 liters- C_initial = initial concentration (unknown)- C_final = final concentration = 60% = 0.6- W_initial = initial amount of water- W_final = final amount of water after removing 8 litersThe amount of acid remains constant, so:C_initial * V = C_final * (V - W_removed)But we don't know C_initial or W_removed.Alternatively, if we assume that the initial concentration is such that removing 8 liters of water results in 60% acidity, then we can set up the equation:C_initial * 24 = 0.6 * (24 - 8)C_initial * 24 = 0.6 * 16C_initial = (0.6 * 16) / 24C_initial = 9.6 / 24C_initial = 0.4 or 40%So, if the initial concentration was 40%, then removing 8 liters of water would result in a 60% concentration. Therefore, the quantity of water to be taken out is 8 liters.But since the problem doesn't provide the initial concentration, we can't perform this calculation. Therefore, the problem is incomplete or there's a misunderstanding in the wording.In conclusion, the problem as stated is unclear and likely missing some information. If we assume that the initial concentration is 40%, then removing 8 liters of water would result in a 60% concentration. Therefore, the quantity of water to be taken out is 8 liters.

Of the five points (4, 15), (8, 25), (14, 42), (19, 48), and (22, 60), what is the sum of the x-coordinates of the points that lie in the region above the line y = 3x + 4 in the coordinate plane?

💡First, I need to determine which of the given points lie above the line ( y = 3x + 4 ). To do this, I'll compare the ( y )-coordinate of each point to the value of ( 3x + 4 ) for the corresponding ( x )-coordinate.1. **For the point (4, 15):** [ 3(4) + 4 = 12 + 4 = 16 ] Since ( 15 < 16 ), this point does not lie above the line.2. **For the point (8, 25):** [ 3(8) + 4 = 24 + 4 = 28 ] Since ( 25 < 28 ), this point does not lie above the line.3. **For the point (14, 42):** [ 3(14) + 4 = 42 + 4 = 46 ] Since ( 42 < 46 ), this point does not lie above the line.4. **For the point (19, 48):** [ 3(19) + 4 = 57 + 4 = 61 ] Since ( 48 < 61 ), this point does not lie above the line.5. **For the point (22, 60):** [ 3(22) + 4 = 66 + 4 = 70 ] Since ( 60 < 70 ), this point does not lie above the line.After evaluating all points, none of them lie above the line ( y = 3x + 4 ). Therefore, the sum of the ( x )-coordinates of the points above the line is ( 0 ).

one night 17 percent of the female officers on a police force were on duty . if 170 police officers were on duty that night and half of these were female officers , how many female officers were on the police force ?

💡First, determine the number of female officers on duty by calculating half of the total officers on duty.Next, recognize that this number represents 17% of the total female officers on the police force.Set up an equation where 85 equals 17% of the total female officers.Solve for the total number of female officers by dividing 85 by 0.17.The final result is 500 female officers on the police force.

If two numbers differ by 2 and their sum is 20, the larger number is:(A) 11(B) 10(C) 9(D) 12(E) 8

💡First, I need to identify the two numbers that differ by 2 and add up to 20. Let's call the smaller number ( x ) and the larger number ( y ).Since the numbers differ by 2, I can write the equation:[y = x + 2]I also know that their sum is 20:[x + y = 20]Substituting the expression for ( y ) from the first equation into the second equation:[x + (x + 2) = 20]Simplifying this:[2x + 2 = 20]Subtracting 2 from both sides:[2x = 18]Dividing both sides by 2:[x = 9]Now, using the expression for ( y ):[y = 9 + 2 = 11]Therefore, the larger number is 11.

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